Предмет: Алгебра, автор: adrianchik

Найдите сумму бесконечной геометрической прогресии -125, 25, -5,..... .

Ответы

Автор ответа: dtnth

b[1]=-125

b[2]=25

b[3]=-5

знаменатель прогрессии

q=b[2]:b[1]

q=25/(-125)=-1/5

сумма прогрессии

S=b[1]/(1-q)

S=-125/(1-(-1/5))=-125/(6/5)=-625/6

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