Предмет: Физика, автор: alinarebrova

Волна распространяется по шнуру со скоростью 2.5 м\с,какова длина волны,если период колебаний точек шнура равен 0,2 с?

Ответы

Автор ответа: larisaorlova65
5
Дано: V=2,5 М/С , Т=0,2с
Найти:λ
Решение. λ=V*T
λ=2,5 м/с *0,2с=0,5 м
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