Предмет: Физика, автор: deniska34546

6. Тело массой 100 кг, двигаясь по горизонтальной поверхности с некоторой начальной скоростью, проделало путь до остановки 20 м за 10 с. Найдите силу трения, действующую на тело.

Ответы

Автор ответа: mewnet
4
Изменение кинетической энергии тела равно работе силы трения.
mV₀²/2=FS
mV₀²=2FS
F=mV₀²/2S
чтобы найти силу трения, нам надо найти начальную скорость тела. для этого из формулы S= \frac{V_0^2}{2a} выразим а: a= \frac{V_0^2}{2S} . теперь подставим в формулу V_0=at вместо а полученное нами выражение: V_0= \frac{V_0^2}{2S}t \\ V_0= \frac{2S}{t}.
F= \frac{4mS^2}{2t^2S} =\frac{2mS}{t^2} = \frac{2*100*20}{10^2} =40 Н
ответ:40 Н
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