Предмет: Математика, автор: bauyrzhanovad

помогите эти два задания 45 баллов дам

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Автор ответа: Аноним

$67.\\y=4x,\;-1<x<3\\-4<4x<12\\-4<y<12$

$68.\\f(x)=\frac4{9-x}\\a)\;f(5)=\frac4{9-5}=\frac44=1\\f(3)=\frac4{9-3}=\frac46=\frac23\\f(1)=\frac4{9-1}=\frac48=\frac12\\\\b)\;\frac4{9-x}=-4\\4=4x-36\\4x=40\\x=10\\\\\frac4{9-x}=2\\4=18-2x\\2x=14\\x=7\\\\c)\;9-x\neq0\Rightarrow x\neq9\\x\in(-\infty;\;9)\cup(9;\;+\infty)$

bauyrzhanovad: молодец

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