Предмет: Алгебра, автор: ThomasMuller1325

Найдите корни уравнения
x^2-3x-40=0

Ответы

Автор ответа: Аноним
23
x²-3x-40=0
d = b² -4ac = 9 - 4 * (-40) = 9 + 160 = 169
√d = √169 = 13
x₁ = ( -b + √d ) / 2a = ( 3 + 13 ) / 2 = 16 / 2 = 8
x₂ = ( -b - √d ) / 2a = ( 3 - 13 ) / 2 = -10 / 2 = -5
ThomasMuller1325: Благодарю)
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