8х(1+2х)-(х+3)*(4х-3)=2х

8x(1+2x)-(x+3)*(4x-3)=2x

(8x+16x^2)-(4x^2-3x+12x-9)=2x

8x+16x^2-4x^2+3x-12x+9=2x

12x^2-x=2x

12x^2-x-2x=0

3x(4x-1)=0

3x=0               4x-1=0

x=0                 4x=1

x=1/4

Ответ:x=0,x=1/4