Предмет: Алгебра, автор: заяц9090

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Автор ответа: dtnth

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$\frac{45\frac{5}{12}-43\frac{13}{18}}{6.1}=\\\\(45-43+\frac{5}{12}-\frac{13}{18}):\frac{61}{10}=\\\\(2+\frac{5*3}{12*3}-\frac{13*2}{18*2})*\frac{10}{61}=\\\\\frac{2*36+15-26}{36}*\frac{10}{61}=\\\\\frac{61*10}{36*61}=\frac{10}{36}=\frac{5}{18}$
ответ: 5/18

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