Предмет: Алгебра, автор: IrinaNya

Решите неравенство пожалуйста! У меня плохо с тригонометрией(

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Автор ответа: nKrynka

Решение
sin2x > √3cos2x разделим на cos2x ≠ 0
tg2x > √3
arctg√3 + πn < 2x < π/2 + πn, n∈Z
π/3 + πn < 2x < π/2 + πn, n∈z
π/6 + πn/2 < x < π/4 + πn/2, n∈z

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