Предмет: Химия, автор: msMary98

при действии на смесь Al и Cu массой 4 грамма хлороводородной кислотой выделилось 3.36 л газа. определить состав смеси

Ответы

Автор ответа: Аноним

7

54г_____________________67.2 л
2Al. + 6HCl=2AlCl3+3H2
х=2.7г__________________3.36л

m(Cu)=4-2.7=1.3г
w(Cu) =1.3*100%/4=32.5%
w(Al)=2.7*100%/4=67.5%

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