Предмет: Алгебра, автор: LLlKOJlA11

(x-3)(x+7)-(x+8)(x-4)=11 докажите тождество

Ответы

Автор ответа: mukus13

13

$x^{2} +7x-3x-21- x^{2} +4x-8x+32=11$
11=11

Автор ответа: vsabeshkina

8

(x-3)(x+7)-(x+8)(x-4)=x^2+7*x-3*x-21-x^2+4*x-8x+32=(-21)+32=11

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