Предмет: Алгебра, автор: студент289

найти предел :lim n -знак бесконечности 2n-3/4n-8. срочно!!!

Ответы

Автор ответа: natylia64

2

$\lim_{n \to \infty} 2n-3/4n-8=n(2-3/n)/n(4-8/n)=2-3/∞/4-8/∞=2/4=1/2$

∞ - знак бесконечности

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