Предмет: Математика, автор: NeKiT828

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Автор ответа: NNNLLL54

$\int _1^{e^2}\frac{2\sqrt{u}+5-7u}{u}du=\int _1^{e^2}(\frac{2}{\sqrt{u}}+\frac{5}{u}-7)du=(2\cdot 2\sqrt{u}+5\cdot ln|u|-7u)_1^{e^2}=\\\\=4\sqrt{e^2}+5\cdot ln|e^2|-7e^2-(4+5ln1-7)=\\\\=4\cdot e+5\cdot 2-7e^2-4-0+7=13+4e-7e^2$

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