Предмет: Алгебра, автор: deleted824590

Найдите сумму 29 первых членов арифметической прогрессии (pn),если:

p1=18,7; p29=-19.6

Ответы

Автор ответа: pashok1432
0

S(n)=(p(1)+p(29))/2*n
S(29)=(18.7+(-19.6))/2 *29=-0,9/2*29=-13,05

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