Предмет: Математика, автор: даня20

пасажир поезда ,идущего со скоростью 50 км/ч,заметил ,что встречный поезд шел мимо него 10 сек.Определите длину встреч. поезда,если его скорость -58 км/ч

Ответы

Автор ответа: leonidov

0

1)50+58=108(км/ч)-скорость встреч. поездов

108(км/ч)=30(м/с)

2)30*10=300(м)- длина встречного поезда

Ответ:300м

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