Предмет: Информатика, автор: DaraA

Решите задачу в Кумире:Сила тока в цепи электрической лампы равна 0,3А. Сколько электронов проходит через поперечное сечение спирали за 5 мин?

Ответы

Автор ответа: Аноним

Дано:

t=5мин=300сек
qс=1.6*10^-19
Найти:

ne-?

Решение:
I=q/t
q=I*t
ne=q/qe=(I*t)/qe
ne=(0.3*300)/(1,6*10^-19)=примерно $5,6 *10^{20}$

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