Предмет: Химия, автор: евгений101

какая масса соли получиться при взаимодействии хлорида кальция 1.26 азотной кислоты?

Ответы

Автор ответа: wasurenagusa

0

CaCl2 + 2HNO3 = Ca(NO3)2 + 2HCl
n(HNO3) = 1,26/63 = 0,02 моль
n(Ca(NO3)2) = 0,02/2 = 0,01 моль
m(Ca(NO3)2) = 0,01*164 = 1,64 г

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