Предмет: Математика, автор: ferid2016

Стороны треугольника 10,12и14см.Найдите периметр трапеции отсекаемой средней линией,проведенной параллельно большой стороне этого треугольника

Ответы

Автор ответа: Suzanet
0
Средняя линия параллельна большей стороне (14 см) и соответственно будет равна половине этой стороны (7 см).
Так как линия средняя, то две другие стороны треугольника она будет делить пополам , а значит, на 5 и 6 см.
Трапеция будет состоять из: большая сторона = 14 см, средняя линия = 7 см, половинки двух других сторон (5 и 6 см)
Р = 5+6+7+14 = 32 - периметр её.
Приложения:
Автор ответа: Suzanet
0
добавила рисунок)
Автор ответа: Suzanet
0
АМNC - соответственно ваша трапеция рассматриваемая
Автор ответа: ferid2016
0
спасибо
Автор ответа: ferid2016
0
можно еще дать
Автор ответа: ferid2016
0
Основания трапециив отношении 2:3,а средняя линия 7,5см.Найдите основания.
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