Предмет: Алгебра,
автор: sonyar2507
помогите решить пожалуйста:)))
Приложения:
Ответы
Автор ответа:
0
1)
![frac{b+2}{4b^3-4b^2+b}- frac{2-b}{1-8b^3}* frac{4b^2+2b+1}{2b^2+b}= \ \
= frac{b+2}{b(4b^2-4b+1)}- frac{2-b}{(1-2b)(1+2b+4b^2)}* frac{4b^2+2b+1}{b(2b+1)}= \ \
= frac{b+2}{b(2b-1)^2}- frac{2-b}{b(1-2b)(2b+1)}= frac{b+2}{b(2b-1)^2}+ frac{2-b}{b(2b-1)(2b+1)}= \ \
= frac{(b+2)(2b+1)+(2-b)(2b-1)}{b(2b-1)^2(2b+1)}= frac{2b^2+4b+b+2+4b-2b^2-2+b}{b(2b-1)^2(2b+1)}= \ \
= frac{10b}{b(2b-1)^2(2b+1)}= frac{10}{(2b-1)^2(2b+1)}](https://tex.z-dn.net/?f=+frac%7Bb%2B2%7D%7B4b%5E3-4b%5E2%2Bb%7D-+frac%7B2-b%7D%7B1-8b%5E3%7D%2A+frac%7B4b%5E2%2B2b%2B1%7D%7B2b%5E2%2Bb%7D%3D+%5C++%5C+%0A%3D++frac%7Bb%2B2%7D%7Bb%284b%5E2-4b%2B1%29%7D-+frac%7B2-b%7D%7B%281-2b%29%281%2B2b%2B4b%5E2%29%7D%2A+frac%7B4b%5E2%2B2b%2B1%7D%7Bb%282b%2B1%29%7D%3D+%5C++%5C+%0A%3D+frac%7Bb%2B2%7D%7Bb%282b-1%29%5E2%7D-+frac%7B2-b%7D%7Bb%281-2b%29%282b%2B1%29%7D%3D+frac%7Bb%2B2%7D%7Bb%282b-1%29%5E2%7D%2B+frac%7B2-b%7D%7Bb%282b-1%29%282b%2B1%29%7D%3D+%5C++%5C+%0A%3D+frac%7B%28b%2B2%29%282b%2B1%29%2B%282-b%29%282b-1%29%7D%7Bb%282b-1%29%5E2%282b%2B1%29%7D%3D+frac%7B2b%5E2%2B4b%2Bb%2B2%2B4b-2b%5E2-2%2Bb%7D%7Bb%282b-1%29%5E2%282b%2B1%29%7D%3D+%5C++%5C+%0A%3D+frac%7B10b%7D%7Bb%282b-1%29%5E2%282b%2B1%29%7D%3D+frac%7B10%7D%7B%282b-1%29%5E2%282b%2B1%29%7D++++++++++++++++ "frac{b+2}{4b^3-4b^2+b}- frac{2-b}{1-8b^3}* frac{4b^2+2b+1}{2b^2+b}= \ \
= frac{b+2}{b(4b^2-4b+1)}- frac{2-b}{(1-2b)(1+2b+4b^2)}* frac{4b^2+2b+1}{b(2b+1)}= \ \
= frac{b+2}{b(2b-1)^2}- frac{2-b}{b(1-2b)(2b+1)}= frac{b+2}{b(2b-1)^2}+ frac{2-b}{b(2b-1)(2b+1)}= \ \
= frac{(b+2)(2b+1)+(2-b)(2b-1)}{b(2b-1)^2(2b+1)}= frac{2b^2+4b+b+2+4b-2b^2-2+b}{b(2b-1)^2(2b+1)}= \ \
= frac{10b}{b(2b-1)^2(2b+1)}= frac{10}{(2b-1)^2(2b+1)}")
2)
![(frac{1}{1-2b} )^2 : frac{10}{(2b-1)^2(1+2b)}=(- frac{1}{2b-1} )^2* frac{(2b-1)^2(1+2b)}{10} = \ \
= frac{1}{(2b-1)^2}* frac{(2b-1)^2(1+2b)}{10}= frac{1+2b}{10}](https://tex.z-dn.net/?f=+%28frac%7B1%7D%7B1-2b%7D+%29%5E2+%3A++frac%7B10%7D%7B%282b-1%29%5E2%281%2B2b%29%7D%3D%28-+frac%7B1%7D%7B2b-1%7D+%29%5E2%2A+frac%7B%282b-1%29%5E2%281%2B2b%29%7D%7B10%7D+%3D+%5C++%5C+%0A%3D+frac%7B1%7D%7B%282b-1%29%5E2%7D%2A+frac%7B%282b-1%29%5E2%281%2B2b%29%7D%7B10%7D%3D+frac%7B1%2B2b%7D%7B10%7D++++ "(frac{1}{1-2b} )^2 : frac{10}{(2b-1)^2(1+2b)}=(- frac{1}{2b-1} )^2* frac{(2b-1)^2(1+2b)}{10} = \ \
= frac{1}{(2b-1)^2}* frac{(2b-1)^2(1+2b)}{10}= frac{1+2b}{10}")
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