срочно помогите1!!!11!1!11

1) y^2-y/1-y^2 = y(y-1)/(y-1)(y+1) = y/y+1
2) a^2x-ax^2/x^2-ax = ax(a-x)/x(x-a) = -ax(a-x)/x(a-x) = -ax/x = -a
3) z^2-3z/9-6z+z^2 = z(z-3)/(z-3)^2 = z/z-3

во вложении------------------------