написать уравнение реакций:глюкоза-молочная кислота-лактат натрия

1.C6H12O6=2CH3-CH(OH)-COOH
СH3-CH(OH)-COOH+NaOH=CH3-CH(OH)-COONa+H2O

1)6CO2+6H2O=C6H12O6+6O2

CH2OH-(CHOH)4-COH+H2=CH2OH-(CHOH)4-CH2OH

2)CH2OH(CHOH)4-COH+Ag2O=CH2OH-(CHOH)4-COOH+2Ag

CH2OH-(CHOH)4-COOH+NaOH=CH2OH-(CHOH)4-COONa+H2O

3)C6H12O6=2C2H5OH+2CO2

C2H5OH=C2H4+H2O

C6H12O6=H3C-CH-COOH+2CO2+2H2

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                               CH3