Предмет: Геометрия, автор: anton10112001

Дано: АВСД параллелограмм. ВЕ биссектриса = 2 см. Угол СВЕ= 60 градусов. АВ= 10 см. Найти АД и ДС!

Ответы

Автор ответа: ssoxo

0

∠СВЕ=∠АВЕ=60°.
∠АВЕ=∠ВЕС как накрест лежащие при параллельных АВ и СД и секущей ВЕ, значит ∠СВЕ=∠ВЕС=60°, значит тр-ник ВЕС равносторонний, значит ВС=ВЕ=2 см.
В параллелограмме АВСД АД=ВС=2 см, ДС=АВ=10 см - это ответ.

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Автор ответа: anton10112001

0

Спасибо большое...

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