задание 8................

дано
W(С)=81.82%=0.8182
W(H)=18.18%=0.1818
V(CxHy)=1 L
m(CxHy)=2.6 g
--------
CxHy-?
M(CxHy)=m(CxHy)*Vm/V(CxHy)=2.6*22.4/1=58.24g/mol
CxHy/58.24 = 0.8182/12 : 0.1818/1
CxHy=4:10
C4H10
ответ бутан