Предмет: Физика, автор: Tolua1337

усок льда нагревали в лабораторной печи в течение длительного времени при постоянной мощности. За 5 минут температура льда повысилась от 253 К до 273 К, а далее не изменялась (т.к. лёд начал таять). Сколько времени пройдёт от начала нагревания до момента, когда лёд полностью расплавится? Удельная теплоёмкость льда равна 2100 Дж/(кгК), удельная теплота плавления льда равна 3,310^5 Дж/кг.

Ответы

Автор ответа: ЮрВас

Для нагр льда потребуется Q₁=mcΔt.
Для плавления Q₂=mλ.
Это больше в
n=mλ/mcΔt=λ/cΔt=330000/(2100*20)=330/42=7,86 раза.
Значит для плавления потр времени t₂=5*7,86=39,3 мин.
Всего t=t₁+t₂=5+39.3=44,3 мин.
Ответ: 44,3 мин

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