решите пожалуйста 237 срочно

1) log₁/₅ 9+2log₁/₅5/3= 2log₁/₅ 3+2log₁/₅5/3=2(log₁/₅ 3+log₁/₅5/3)=2log₁/₅ 5=
=2log₁/₅ (1/5)^(-1)=-2
2) log₃ 8+3log₃9/2=3log₃ 2+3log₃9/2=3(log₃ 2+log₃9/2)=3log₃( 2·9/2)=3log₃(9)=
=3log₃(3²)=6

3)log₇196-2log₇2=log₇196-log₇2²=log₇(196/2²)=log₇(196/4)=log₇49=log₇(7²)=2

4)log₂(√3)+(1/2)log₂(4/3)=(1/2)log₂(3)+(1/2)log₂(4/3)=(1/2)log₂(3·4/3)==(1/2)log₂(4)=(1/2)·2=1