Предмет: Физика, автор: kuteshas

Под действием постоянной силы 0,003 н шарик в пеовуюсекундупрошол 15 см опредилите мпссу шарика

Ответы

Автор ответа: sokolovvovikn

0

S=a*t^2/2
a=2*S/t^2=2*0,15/1^2=0,3 м/с2
m=F/a=0,003/0,3=0,01 кг

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