Предмет: Геометрия, автор: aktanshulenov

80 баллов за правильный ответ. В треугольнике ABC AB=10 см. Через точку К на стороне AB проведена прямая КМ параллельно АС, АК=5 см. Докажите, что ВМ=МС.

Ответы

Автор ответа: MadelinAmo

АBC AB-Ak=5cm
AB+K-5=15cm

Автор ответа: MajorPayne

Видно, что KM- средняя линия, и потому что она параллельна основанию и делит стороны треугольника на равные части (AB = 2AK)
Значит BM = MC уже по доказанному ( AK = KB)

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