помогите решить
x^2/3=1/27
9x^3-x=0
2x^2+4x^3=0

1)x^2/3=1/27
27x^2=3
x^2=1/9
x=+,- 1/3
2)9x^3-x=0
X(9x^2-1)=0
X=0
9x^2-1=0
9x^2=1
X^2=1/9
X=+,- 1/3
3)2x^2+4x^3=0
2x^2(1+2x)=0
x=0
1+2x=0
2x=-1
X=-1/2