Предмет: Алгебра, автор: nhhngfnb

помогите с заданиями по Алгебре

Приложения:

Ответы

Автор ответа: NNNLLL54
0
1)  Не имеет решений уравнение cosx=1,5  , так как значения
      функции  y=cosx  не превышает 1 :  -1 ≤ cosx ≤ 1 .

2)quad sin(pi -3x)cdot cosx+cos3xcdot cos(frac{3pi}{2}-x)=\\=sin3xcdot cosx+cos3xcdot (-sinx)=sin3xcdot cosx-cos3xcdot sinx=\\=sin(3x-x)=sin2x\\3)quad 4sinfrac{x}{2}cdot cos frac{x}{2} =sqrt3\\star ; ; 2sin alpha cdot cos alpha =sin2 alpha ; ; star \\2sinx=sqrt3\\sinx= frac{sqrt3}{2} \\x=(-1)^{k}cdot frac{pi }{3}+pi k; ,; kin Z
    
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