Предмет: Алгебра, автор: vika122566515616526

найдите вторые производные y = lnsinx

Ответы

Автор ответа: AlbuRin

G(x) = y " = (lnsinx) " = 1/sinx *(sinx) " =1/sinx*cosx = ctgx первая производная

G ' (x) = (ctgx) " = -1/sin^2x вторая производная

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