Предмет: Алгебра, автор: Alman1

Найдите производную функции f(x)=e^x cosx

Ответы

Автор ответа: laymlaym2

$f'(x)=(e^x*cosx)'=(e^x)'*(cosx)+(e^x)*(cosx)'=\=e^x*cosx+e^x*(-sinx)=e^x(cosx-sinx)$

Автор ответа: onahochetnamars

(e^x*cosx)'=(e^x)'*(cosx)+(e^x)*(cosx)'=(e^x)*cosx-(e^x)*sinx=(e^x)*(cosx-sinx)

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