Предмет: Алгебра, автор: gagaga15

Помогите плез пилить 4 примера, даю много баллов

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Ответы

Автор ответа: Cream16

$2)( frac{c}{c+6} + frac{36+c^2}{36-c^2} - frac{c}{c-6} ): frac{6c+c^2}{(6-c)^2}= \ ( frac{c}{c+6} + frac{(6+c)(6+c)}{(6-c)(6+c)} - frac{c}{c-6} ): frac{6c+c^2}{(6-c)^2}= \ ( frac{c}{c+6} + frac{(6+c)}{(6-c)} + frac{c}{6-c} ): frac{6c+c^2}{(6-c)^2}= \ ( frac{6c-c^2+36+c^2+6c+c^2}{(6+c)(6-c)} ): frac{6c+c^2}{(6-c)^2}= \ ( frac{c^2+12c+36}{(6+c)(6-c)} ): frac{6c+c^2}{(6-c)^2}= \ ( frac{(c+6)^2}{(6+c)(6-c)} ): frac{6c+c^2}{(6-c)^2}= \$

$frac{(c+6)}{(6-c)} : frac{6c+c^2}{(6-c)^2}= \ frac{(c+6)}{(6-c)} * frac{(6-c)^2}{c(6+c)}= frac{6-c}{c};$

$3)( frac{2m}{n+2m}- frac{4m^2}{n^2+4m^2+4mn} ):( frac{2m}{n^2-4m^2}+ frac{1}{2m-n} )= \ ( frac{2m}{n+2m}- frac{4m^2}{(n+2m)^2} ):( frac{2m}{(n-2m)(n+2m)}- frac{1}{n-2m})= \ ( frac{2mn+4m^2-4m^2}{(n+2m)^2} ):( frac{2m-n-2m}{(n-2m)(n+2m)} )= \ frac{2mn}{(n+2m)^2} *(- frac{(n-2m)(n+2m)}{n} )= \ - frac{2m*(n-2m)}{(n+2m)} = frac{4m^2-2mn}{(n+2m)} ;$

$4)( frac{2p}{2p+q}- frac{4p^2}{4p^2+q^2+4pq} ):( frac{2p}{4p^2-q^2}+ frac{1}{q-2p} )= \ ( frac{2p}{2p+q}- frac{4p^2}{(2p+q)^2)} ):( frac{2p}{(2p-q)(2p+q)}- frac{1}{2p-q} )= \ frac{4p^2+2pq-4p^2}{(2p+q)^2} } : frac{2p-2p-q}{(2p+q)(2p-q)} = \ frac{2pq}{(2p+q)^2} } * (- frac{(2p-q)(2p+q)}{q} )} = \ -frac{2p(2p-q)}{2p+q} = frac{q-4p^2}{2p+q} ;$