решить уравнение:

(5/(y-2))-(4/(y-3))=1/y

(5/(y-2))-(4/(y-3)=1/y |*y(y-2)(y-3), y не=0, у не=2, у не=3

5y(y-3) -4y(y-2)=(y-2)(y-3)

5y^2-15y-4y^2+8y=y^2-2y-3y+6

-7y+5y=6

-2y=6

y=-3

(5/(y-2))-(4/(y-3))=1/y

5y(y-3)-4y(y-2)=1(y-2)(y-3)

5y^2-15y-4y^2+8y=y^2-2y-3y+6

-2y=6

y=-3