Помогите решить уравнение

log3(log4(log²3(x-3)))=0,
О.Д.З. х-3>0, x>3,
log3(log4(log²3(x-3)))=log3(1),
log4(log3²(x-3))=1,
log4(log²3(x-3))=log4(4),
log²3(x-3)=4,
log3(x-3)=±2

1)log3(x-3)=2 2)log3(x-3)=-2
log3(x-3)=log3(9) log3(x-3)=log3(1/9)
x-3=9 x-3=1/9
x=12 x=28/9