Предмет: Математика, автор: thankay

Здравствуйте Решите пожалуйста задание

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Ответы

Автор ответа: Hogpa
0
а) 1 день - 4050 км ,на  760 км м,чем во 2 день
2 день - ?
3 день - ?,на 390 км б,чем во 2 день.
Решение
1) 4050+760= 4810 (км) - во 2 день
2) 4810+390= 5200 (км) - в 3 день
3) 4050+4810+5200=14060 (км)
Ответ: Летчик пролетел за 3 дня 14060 км
б) Первый цех:
Слесари - 456
Токари - ?,на 120 чел. б,чем Слесарей
Второй цех - ?, на 149 чел. м.,чем в первому цеху.
Решение
1) 456+120=576 (чел) - Токарей в первом цеху
2) 456+576= 1032 ( чел) - всего в первом цеху
3)1032-149=883 ( чел) - во втором цеху
4)1032+883=1915 ( чел ) - всего
Ответ : 1915 человек
№3
Первая к. - 18 км 350 м
Вторая к. - на 3 км 200 м больше,чем первая
Решение
8 км 350 м=18350 (м)
3км 200 м=3200 (м)
18350+3200=21550 (м) - прошла вторая команда
18350+21550= 39900 м =39 км 900м - расстояние между посёлками
Ответ: 39 км 900 м


Автор ответа: zaikanastenka0
0
а) 1)4050+760=4810(км)-второй день
2)4810+390=5200( км)- третий день
3)4050+4810+5200=14060(км)-за три дня
Ответ:14060 км.
Б)1) 120+456=576-слесарей в первом цехе
2)576+456=1032-человек в первом цеху
3) 1032-149=883-человек во втором цеху
4) 1032+883=1915-человек во обоих цехах
Ответ:1915 человек.
В)1)18350+3200=21550(км)
2)18350+21550=39900(км)
Ответ:39 км 900 м.
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