Предмет: Алгебра, автор: andromeda31

Помогите с логарифмами!!!!!

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Ответы

Автор ответа: xtoto

$log_2(4x+1) textless log_2(2x+5)\ 4x+1 textless 2x+5 and x textgreater -frac{1}{4} and x textgreater -frac{5}{2}\ 2x textless 4 and x textgreater -frac{1}{4}\ x textless 2 and x textgreater -frac{1}{4}\ xin (-frac{1}{4}; 2)$

$log_{0.2}(x^2-x-2) textgreater log_{0.2}(-x^2+2x+3)\ x^2-x-2 textless -x^2+2x+3 and x^2-x-2 textgreater 0 and -x^2+2x+3 textgreater 0\ 2x^2-3x-5 textless 0 and xin (-infty;-1)cup(2;+infty) and xin(-1;3)\ 2x^2+2x-5x-5 textless 0 and xin(2;3)\ 2x(x+1)-5(x+1) textless 0 and xin(2;3)\ (x+1)(2x-5) textless 0 and xin(2;3)\ [x-(-1)]*[x-2.5] textless 0 and xin(2;3)\ xin (-1; 2.5) and xin(2;3)\ xin(2;2.5)$

$log_{x-1}(9-x^2) textless 0\\ left { {{log_{x-1}(9-x^2) textless log_{x-1}(1)} atop {x-1 textgreater 0 and x-1 neq 1} and 9-x^2 textgreater 0} right.; \ left { {{log_{x-1}(9-x^2) textless log_{x-1}(1)} atop {0 textless x-1 textless 1 and x^2-9 textless 0} right. or left { {{log_{x-1}(9-x^2) textless log_{x-1}(1)} atop {x-1 textgreater 1 and x^2-9 textless 0} right.;\ left { {{9-x^2 textgreater 1} atop {1 textless x textless 2 and (x-3)(x+3) textless 0} right. or left { {{9-x^2 textless 1} atop {x textgreater 2 and (x-3)(x+3) textless 0} right.;\$

$left { {{x^2-8 textless 0} atop {1 textless x textless 2 and -3 textless x textless 3} right. or left { {{x^2-8 textgreater 0} atop {x textgreater 2 and -3 textless x textless 3} right.;\ left { {{(x-2 sqrt{2})(x+2 sqrt{2} ) textless 0} atop {1 textless x textless 2} right. or left { {{(x-2 sqrt{2})(x+2 sqrt{2} ) textgreater 0} atop {2 textless x textless 3} right.;\ left { {{-2 sqrt{2} textless x textless 2 sqrt{2}} atop {1 textless x textless 2} right. or left { {{x textless -2 sqrt{2} or x textgreater 2 sqrt{2}} atop {2 textless x textless 3} right.;\$

$left { {{xin (-2 sqrt{2}; 2sqrt{2})} atop {xin(1; 2)} right. or left { {{xin (-infty; -2 sqrt{2}) cup (2 sqrt{2}; +infty)} atop {xin(2; 3)} right.;\\ xin(1; 2)} or xin(2 sqrt{2} ; 3)} right.;\\ xin(1; 2)} cup (2 sqrt{2} ; 3)} right..\$

$log_x(x^3-x^2-2x) textless 3\\ left { {{x^3-x^2-2x textgreater x^3} atop {0 textless x textless 1} and x^3-x^2-2x textgreater 0} right. or left { {{x^3-x^2-2x textless x^3} atop {x textgreater 1 and x^3-x^2-2x textgreater 0}} right.;\\ left { {{2x^3-x^2-2x textgreater 0} atop {0 textless x textless 1} and xin(-1;0)cup (2;+infty)} right. or left { {{x^2+2x textgreater 0} atop {x textgreater 1 and x(x-2)(x+1) textgreater 0}} right.;\$

$left { {{2x^3-x^2-2x textgreater 0} atop {xin{}} right. or left { {{x(x+2) textgreater 0} atop {x textgreater 1 and xin(-1;0)cup (2;+infty)}} right.;\\ xin{} or left { {{xin(-infty;-2)cup (0;+infty)} atop {xin(2; +infty)}} right. \\ xin{} or xin(2; +infty)\\ xin(2; +infty)$

Автор ответа: xtoto

сейчас последнее исправлю

Автор ответа: andromeda31

спасибо

Автор ответа: xtoto

и первое, обожди использовать мое решение

Автор ответа: xtoto

сейчас все ок

Автор ответа: m11m

!!!!!!!!!!l!!!!!!!!!!!!!!!!

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