Предмет: Химия, автор: watasiwanekodesu4

Помогите срочно с объяснением пожалуйста даю много баллов!!!
Какой объём воздуха требуется для сжигания 20 л пропина и 20 л бутина?

Ответы

Автор ответа: kasha6667
1

на 1 объем бутина требуется 5,5 объемов О2.
Следовательно, кислорода пойдет 50 * 5,5 = 275 л, воздуха потребуется 275 / 0,2 = 1375 л
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