Предмет: Физика, автор: daryalyub

ОТВЕТ: 80% НАПИШИТЕ РЕШЕНИЕ!!!!!
Определите полезную и затраченную работу при подъеме груза массой m = 2,0 кг на высоту h = 0,40 м, если приложена сила F = 12,5 Н. Определите КПД установки.

daryalyub: и мне))))

daryalyub: Физику то я уж всегда не буду любить...

Ответы

Автор ответа: Аноним

m=2кг
F=mg=2*10=20H
Ап=FS=20*0,4=8Дж
Ас=12,5*0,8=10Дж
КПД=(Ап/Ас)*100%=(8/10)*100%=80%
КПД подвижного блока 80%

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