Предмет: Алгебра, автор: zxq2003

Решите неравенство и изобразите множество его решений
на координатной прямой
1) 12х - 16 > 11х + 2(3х + 2).
2)8 - 5(х + 2) < 4(1 - х).


zxq2003: Help plsssssssssssss

Ответы

Автор ответа: zhenyaM2002
1
1)
12x  - 16 > 10x + 2(3x + 2)
12x  - 16  >  10x  + 6x  + 4
12x  - 16 >  16x  + 4
12x  - 16x > 4 + 16
- 4x >  20                   |×(-1) ⇒ меняем знак неравенства
4x <  - 20
x <  - 5
x∈( - ∞ ;  - 5)

2)
8 -  5(х + 2) <  4(1 - x)
8  - 5x  - 10 <  4  - 4x
-5x  - 2 <  4 - 4x
-5x  + 4x <  4 + 2
-x <  6                         |× (-1)
x >  -  6 
x∈ ( - 6 ;  +∞ )
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