п0м0гите!!!!!!!111!!!!!!

x(x² + 2x + 1) = 6(x + 1);

x(x + 1)² = 6(x + 1);

x(x + 1)² - 6(x + 1) = 0;

(x + 1)(x(x + 1) - 6) = 0;

(x + 1)(x² + x - 6) = 0;

x + 1 = 0;           x² + x - 6 = 0;

x₁ = -1;              x₂ = -3;  x₃ = 2

Ответ: -1; -3; 2.