Предмет: Алгебра, автор: 607408prekrassnaya

помогите срочняк с алгеброй

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Ответы

Автор ответа: NazDuDa

$\frac{14 {a}^{2} {b}^{5} }{21 {a}^{3} {b}^{2} } = \frac{2 {b}^{3} }{3a} \\ \frac{3 {x}^{2} (x + 7)}{6(x + 7)} = \frac{ {x}^{2} }{2} \\ \frac{b(a + 2)}{(a - 2)(a + 2)} = \frac{b}{a - 2} \\ \frac{(x + 3) ^{2} }{(x + 3)( {x}^{2} - 3x + 9) } = \frac{x + 3}{ {x}^{2} - 3x + 9 }$

607408prekrassnaya: спасибо

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