Помогите! вычислите омегу K²CO³; MgCl²

1) Mr(K2CO3) = 39*2 + 12 + 16*3 = 138

W(K)1) Mr(K2CO3) = 39*2 + 12 + 16*3 = 138

W(K) = Ar(K) *n / Mr(K2CO3) *100% = 39*2 / 138  *100% = 56%

W(C) = Ar(C) *n / Mr(K2CO3)  *100% = 12*1 / 138  *100% = 9%

W(O) = Ar(O) * n / Mr(K2CO3)  *100% = 16*3 / 138  *100% = 35%

2) Mr(MgCl2) = 24 + 35,5*2 = 95

W(Mg) = Ar(Mg) * n / Mr(MgCl2)  *100% = 24*1 / 95  *100% = 25%

W(Cl) = Ar(Cl) *n / Mr(MgCl2)  *100% = 35,5*2 / 95 * 100% = 75%