Пожалуйста решите задачу.

дано

m(CuSO4) = 32 g

m(NaOH) = 4 g

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m(Cu(OH)2)-?

M(CuSO4) = 160 g/mol

n(CuSO4) = m/M = 32 / 160 = 0.2 mol

M(NaOH) = 40 g/mol

n(NaOH) = m/M  = 4 / 40 = 0.1 mol

n(CuSO4) > n(NaOH)

2n(NaOH) = n(Cu(OH)2)

n(Cu(OH)2) = 1/2 = 0.5 mol

M(Cu(OH)2) = 98 g/mol

m(Cu(OH)2) = n*M = 0.5 * 98 = 4.9 g

ответ 4.9 г