Предмет: Физика, автор: ioiuhgjy6709

К телу прикладывают силу в 36 Н и прямолинейно перемещают его на расстояние 24 м. Сила приложена под углом 60° к горизонту.

Какова величина совершённой работы?

Ответ: A =
Дж.

Ответы

Автор ответа: gaponovahelena

4

A= Fx*S= F*cosA * S= 36*cos 60*24=36*(1/2)*24= 432 ДЖ

Автор ответа: vladyandymokk13

6

A = FScos(a) = 36 * 24 * cos60° = 432 Дж

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