Предмет: Физика, автор: azamat5555

На динамометр подвешен груз массой 2 кг.
Один раз динамометр подняли с ускорением
2 м/с2, а другой раз опустили с таким же ускоре-
нием. Определите разность его показаний (H) в
этих двух случаях.

Ответы

Автор ответа: tana20101997

Ответ:

Объяснение:

P1=m*(g+a)=2*(10+2)=24 H P2=m*(g-a)=2*(10-2)=16 H dP=P1-P2=24-16= 8 H

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*

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*

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*

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*

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*

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