Предмет: Математика, автор: jjky

Найдите угол между диагоналями прямоугольника, если диагональ образует с одной из его сторон угол 28°.

Ответы

Автор ответа: axatar

6

Ответ:

56° и 124°

Пошаговое объяснение:

Пусть ABCD прямоугольник и О точка пересечения диагоналей. По условию ∠BAO= 28°. Так как в прямоугольника ΔAOB равнобедренный и AO=OB, то ∠ABO=28°. В силу этих заключений имеем ∠AOB=180°-∠BAO-∠ABO=180°-2·28°=180°-56°=124°. Тогда другой угол 180°-124°=56°

jjky: Спасибо!!!

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