Предмет: Геометрия, автор: SPICR

Найдите синус угла АОВ изабраженый на рисунке, помогите пожалуйста

Приложения:

Ответы

Автор ответа: Аноним

Ответ:

0,6

Объяснение:

1)На рисунке из точки В опустим перпендикуляр, получим точку Н. Отрезок ВН=3 ( ед), Отрезок ОН= 4(ед).

2)ΔОВН-прямоугольный , по т. Пифагора ОВ=√3²+4²=√25=5

3)Синусом острого угла прямоугольного треугольника называется отношение противолежащего этому углу катета ( т.е ВН) к гипотенузе (т.е.ОВ). sin∠О=3/5=0,6

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