Предмет: Математика, автор: nailaysen1109

Номер 600, задача А

Приложения:

Ответы

Автор ответа: Pepino
1

Ответ:

Пошаговое объяснение:

На рис. 63 (а) изображены две пространственные фигуры:

1. Конус.

2. Полусфера.

Определяем объем конуса.

Vкон.= h/3 π r², где

V - объем конуса

h - высота конуса

π - число пи (3,14)

r - радиус конуса

h = 3

π = 3,14

Т.к. высота всей фигуры равна 4, то 4 – 3 = 1 = r

Vкон. = 3/3 • 3,14 • 1² = 3,14

Определяем объем полусферы.

Для этого определим объем шара:

Vшар. = 4/3 π r³

Vшар. = 4/3 • 3,14 • 1³ ≈ 4,187

Vполусф. = 4,187 : 2 ≈ 2,094

Объем полной фигуры:

Vфиг. = Vкон. + Vполусф.

Vфиг. = 3,14 + 2,094 ≈ 5,234

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