Предмет: Алгебра, автор: dapsten123

(4+5х)²-(9-6х)²

2(m-3n)²+(m+6n)²

2(3р+2q)²-3(4р+q)²

-9(2х-5у)²-4(3х+7у)²

-5(4n-7m)²-8(2m-3n)²

Ответы

Автор ответа: triolana

файл

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Приложения:

Автор ответа: Svet1ana

$(4+5x)^{2}-(9-6x)^{2}=16+40x+25x^{2}-(81-108x+36x^{2})=16+40x+25x^{2}-81+108x-36x^{2}= (25x^{2}-36x^{2})+(40x+108x)+(16-81)=-11x^{2}+148x-65$

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$2(m-3n)^{2}+(m+6n)^{2}=2(m^{2}-6mn+9n^{2})+m^{2}+12mn+36n^{2}= 2m^{2}-12mn+18n^{2}+m^{2}+12mn+36n^{2}=(2m^{2}+m^{2})+(-12mn+12mn)+(18n^{2}+36n^{2})=3m^{2}+54n^{2}$

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$2(3p+2q)^{2}-3(4p+q)^{2}=2(9p^{2}+12pq+4q^{2})-3(16p^{2}+8pq+q^{2})=18p^{2}+24pq+8q^{2}-48p^{2}-24pq-3q^{2}=(18p^{2}-48p^{2})+(24pq-24pq)+(8q^{2}-3q^{2})=-30p^{2}+5q^{2}= 5q^{2}-30p^{2}$

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$-9(2x-5y)^{2}-4(3x+7y)^{2}=-9(4x^{2}-20xy+25y^{2})-4(9x^{2}+42xy+49y^{2})=-36x^{2}+180xy-225y^{2}-36x^{2}-168xy-196y^{2}=(-36x^{2}-36x^{2})+(180xy-168xy)+(-225y^{2}-196y^{2})= -72x^{2}+12xy-421y^{2}$

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$-5(4n-7m)^{2}-8(2m-3n)^{2}=-5(16n^{2}-56mn+49m^{2})-8(4m^{2}-12mn+9n^{2})= -80n^{2}+280mn-245m^{2}-32m^{2}+96mn-72n^{2}=(-245m^{2}-32m^{2})+(280mn+96mn)+ (-80n^{2}-72n^{2})=-277m^{2}+376mn-152n^{2}$

Приложения:

803638a9c8afd12a22285c05353efdd2.doc

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(4+5х)²-(9-6х)² 2(m-3n)²+(m+6n)² 2(3р+2q)²-3(4р+q)² -9(2х-5у)²-4(3х+7у)² -5(4n-7m)²-8(2m-3n)²

Ответы

(4+5х)²-(9-6х)²

2(m-3n)²+(m+6n)²

2(3р+2q)²-3(4р+q)²

-9(2х-5у)²-4(3х+7у)²

-5(4n-7m)²-8(2m-3n)²