Предмет: Физика, автор: larisaabs

Санки,скользившие по горизонтальной поверхности,остановились,пройдя расстояние 25 метров.Определите начальную скорость санок ,если коэффициент трения 0,05

Ответы

Автор ответа: Mamedov12
0

Fтр=ma - по II закону Ньютона

Поверхность горизонтальная => Fтр= μmg

μmg=ma I :m

a=μg

S=(u²-u²0)/2μg

u= √(u²+2μgS)

u= √(0+2*0.05*10*25) = √25 = 5м/с

Ответ: 5м/с

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