Предмет: Алгебра, автор: suprunenkoirina1981

x2-6\x-3=х\x-3 Помоготе решть

Ответы

Автор ответа: Аноним

0

Уравнение таким было?

Приложения:

Автор ответа: Аноним

0

$\frac{x^{2}-6 }{x-3}=\frac{x}{x-3}\\$

Переносим правую часть в левую и приводим к общему знаменателю (в данной ситуации, общий знаменатель: х-3, поэтому оба числителя остаются без изменений):

$\frac{x^{2}-6-x }{x-3} =0$

Находим ОДЗ (область доспустимых значений):

ОДЗ: х-3≠0

х≠3

Решаем квадратное уравнение:

$x^{2} -x-6=0\\$

По теореме Виета:

$x_{1} =3\\x_{2} =-2$

3 не удовлетворяет условию, значит уравнение имеет один корень

Ответ: 2

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